数列{an}的前n项和为Sn,若a1=1,an+1=3Sn(n≧1)则a6=
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数列{an}的前n项和为Sn,若a1=1,an+1=3Sn(n≧1)则a6=
a2=3S1=3a1=3
a3=3S2=3(a1+a2)=12
a4=3S3=3(a1+a2+a3)=48
a5=3S4=3(a1+a2+a3+a4)=192
a6=3S5=3(a1+a2+a3+a4+a5)=768
a3=3S2=3(a1+a2)=12
a4=3S3=3(a1+a2+a3)=48
a5=3S4=3(a1+a2+a3+a4)=192
a6=3S5=3(a1+a2+a3+a4+a5)=768
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