设sin(x+y)=xy,求dy/dx.
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设sin(x+y)=xy,求dy/dx.
cos(x+y)(1+y')=y+xy'
dy/dx=y'=[y-cos(x+y)]/[cos(x+y)-x]
dy/dx=y'=[y-cos(x+y)]/[cos(x+y)-x]
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