main() { char s[]="stop\0\n\""; printf("%d\n",strlen(s)) }
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main() { char s[]="stop\0\n\""; printf("%d\n",strlen(s)) }
//你程序有问题,但是改一下输出4,因为strlen是以‘\0’来作为结束标志的
#include"stdio.h"
#include"string.h"
main() {
char s[]="stop\0\n";
printf("%d\n",strlen(s));
}
#include"stdio.h"
#include"string.h"
main() {
char s[]="stop\0\n";
printf("%d\n",strlen(s));
}
main() { char s[]="stop\0\n\""; printf("%d\n",strlen(s)) }
char s[]=" an apple" ; printf(" %d\n",strlen(s)); A)7 B)8 C)
Char s[]="\113vwxyz\x41"; printf("%d\n",strlen(s)); 为什么结果是7
C语言题目求解char[ ]="\t \chinese\ \girl\n" printf("%d",strlen(s))
main() { char s[]="\\141\141abc\t" ; printf("%d",strlen(s));
#include main() { char *p="abcde\ofghjik\0"; printf("%d\n",s
main(){ char *s,*s1="Here";s=s1;while(*s1)s1++;printf("%d\n"
下面程序的运行结果是: char c[]="\t\v\\\0will\n" printf("%d",strlen);
设有定义:char s[12]={"string"};则printf("%d",strlen(s));的输出值是多少?
设char*1=“12345”,s2=“1234”;执行语句printf(“%d\n”,strlen(strcpy(s1
char *s1="12345",*s2="1234"; printf("%d\n",strlen(strcpy(s1,
有以下程序片段char str[]="ab\n\012\\\"";printf("%d",strlen(str));的输