已知x=a+b,y=a-b,求(x²+y²)²-(x²-y²)
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已知x=a+b,y=a-b,求(x²+y²)²-(x²-y²)²的值
![已知x=a+b,y=a-b,求(x²+y²)²-(x²-y²)](/uploads/image/z/4309355-11-5.jpg?t=%E5%B7%B2%E7%9F%A5x%3Da%2Bb%2Cy%3Da-b%2C%E6%B1%82%28x%26%23178%3B%2By%26%23178%3B%29%26%23178%3B-%28x%26%23178%3B-y%26%23178%3B%29%26%2317)
原式=[(x²+y²)+(x²-y²)][(x²+y²)-(x²-y²)]
=)2x1N)(2y²)
=4(xy)²
=4[(a+b)(a-b)]²
=4(a²-b²)²
=4a^4-8a²b²+4b^4
=)2x1N)(2y²)
=4(xy)²
=4[(a+b)(a-b)]²
=4(a²-b²)²
=4a^4-8a²b²+4b^4
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因式分解(a-b)²(x-y)-(b-a)(y-x)²=(a-b)(x-y)×( )