搜搜做题作业网计算分式：[(4a^2-4a)/(a^2-2a+1)]/[(a+1)/(a-1)-(a-1)/(a+1)]*[1/(3a
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计算分式：[(4a^2-4a)/(a^2-2a+1)]/[(a+1)/(a-1)-(a-1)/(a+1)]*[1/(3a-3)]谢谢了,
![计算分式：[(4a^2-4a)/(a^2-2a+1)]/[(a+1)/(a-1)-(a-1)/(a+1)]*[1/(3a](/uploads/image/z/19767306-66-6.jpg?t=%E8%AE%A1%E7%AE%97%E5%88%86%E5%BC%8F%EF%BC%9A%5B%284a%5E2-4a%29%2F%28a%5E2-2a%2B1%29%5D%2F%5B%28a%2B1%29%2F%28a-1%29-%28a-1%29%2F%28a%2B1%29%5D%2A%5B1%2F%283a)
[(4a^2-4a)/(a^2-2a+1)]/[(a+1)/(a-1)-(a-1)/(a+1)]*[1/(3a-3)] =[4a(a-1)/(a-1)^2]/[4a/(a+1)(a-1)]*[1/3(a-1)] =[4a/(a-1)]/[4a/3(a+1)(a-1)^2] =3(a+1)(a-1)
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