下列方程:①3x^2+1=0 ②根号2x^2-根号3x+1=0
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下列方程:①3x^2+1=0 ②根号2x^2-根号3x+1=0
![](http://img.wesiedu.com/upload/d/7b/d7b57587139e462a53272387727b3c73.jpg)
![](http://img.wesiedu.com/upload/d/7b/d7b57587139e462a53272387727b3c73.jpg)
![下列方程:①3x^2+1=0 ②根号2x^2-根号3x+1=0](/uploads/image/z/16201541-29-1.jpg?t=%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%3A%E2%91%A03x%5E2%2B1%3D0+%E2%91%A1%E6%A0%B9%E5%8F%B72x%5E2-%E6%A0%B9%E5%8F%B73x%2B1%3D0)
1①,②都是
故选B
2 由题知
m^2-2m-1=0
n^2-2n-1=0
且m+n=-b/a=2
mn=-1
即m^2-2m=1
n^2-2n=1
即3m^2-n^2-8m+1
=3m^2-6m-n^2-2m+1
=3(m^2-2m)-n^2-2m+1
=3-n^2-2m+1
=-n^2-2m+4
=-n^2+2n-2n-2m+4
=-(n^2-2n)-2(m+n)+4
=-1-2×2+4
=-1
故选B
2 由题知
m^2-2m-1=0
n^2-2n-1=0
且m+n=-b/a=2
mn=-1
即m^2-2m=1
n^2-2n=1
即3m^2-n^2-8m+1
=3m^2-6m-n^2-2m+1
=3(m^2-2m)-n^2-2m+1
=3-n^2-2m+1
=-n^2-2m+4
=-n^2+2n-2n-2m+4
=-(n^2-2n)-2(m+n)+4
=-1-2×2+4
=-1
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