log3 7·log2 9·log49 a=log4 1/2,则a=
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log3 7·log2 9·log49 a=log4 1/2,则a=
若log3 7·log2 9·log49 a=log4 1/2,则有:
(lg7/lg3)·(lg9/lg2)·(lga/lg49)=lg(1/2)/lg4
即:(lg7/lg3)·(2lg3/lg2)· lga/(2lg7)=-lg2/(2lg2)
化简得:lga/lg2=-1/2
即:lga=(-1/2)lg2=-lg根号2=lg(根号2)/2
所以:a=(根号2)/2
(lg7/lg3)·(lg9/lg2)·(lga/lg49)=lg(1/2)/lg4
即:(lg7/lg3)·(2lg3/lg2)· lga/(2lg7)=-lg2/(2lg2)
化简得:lga/lg2=-1/2
即:lga=(-1/2)lg2=-lg根号2=lg(根号2)/2
所以:a=(根号2)/2
log3 7·log2 9·log49 a=log4 1/2,则a=
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