X²-2x-1=0解根号
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1.根号2x-4x+根号2=0x-2根号2x+1=0x-2根号2x+2=2-1(x-根号2)=1x=根号2±1x1=根号2+1,x2=根号2-12.3x-1=±(x+1)3x-1=x+13x-1=-x
首先须满足2x-1>=0,即x>=1/2方程右边mx>=0,所以也有m>=0方程两边平方,因[x+√(2x-1)][x-√(2x-1)]=x^2-2x+1=(x-1)^2,得:2x+2|x-1|=m^
1.(x-根号3)=3x(根号3-x)x-根号3=0或3x=0或3x=-1x=根号3或x=0或x=-1/32.x²-2(根号3+根号5)x+4根号15=0(x-2根号3)(x-2根号5)=0
2√12-√1/3+√27=4√3-1/3√3+3√3=62/3√3(6又3分之2根号3)x²-2x=0x(x-2)=0x-2=0x1=2x2=0x(3x+1)=1-x3x^2+x=1-x3
记a=x^2+x,方程化为√(4a+1)-√(a+3)=√(a-2)√(4a+1)=√(a-2)+√(a+3)平方:4a+1=2a+1+2√(a-2)(a+3)a=√(a-2)(a+3)再平方a^2=
(1)3x(x-2)+2(x-2)=0(x-2)(3x+2)=0x=2或x=-2/3(2)解方程:(x-根号2)=5x(根号2-x)(x-根号2)-5x(根号2-x)=0(x-根号2)+5x(x-根号
x+根号x+根号(x+2)+根号(x^2+2x)=根号x(根号x+1)+根号(x+2)(根号x+1)=(根号x+1)(根号x+根号(x+2))=3两边同时乘以(根号(x+2)-根号x)得(根号x+1)
根号3X=根号2【x+1】【x-1】3X=2(X^2-1)2X^2-3X-2=0(X-2)(2X+1)=0X1=2X2=-1/2(不合题意,舍去)
(1+根号2)X平方-(3+根号2)X+根号2=0利用十字相乘法得:[(1+根号2)x-1](x-根号2)=0x1=1/(1+根号2)=(根号2)-1x2=根号2
根号(2x-3)+根号(3x-5)=根号(5x-6)两边平方得2x-3+2√(2x-3)(3x-5)+3x-5=5x-62√(2x-3)(3x-5)=2√(2x-3)(3x-5)=1(2x-3)(3x
(x-√2)(x-√3)=0x=√2x=√3
x=(-根号2±根号6)/2
√(2x+1)=√(2-x)2x+1=2-x3x=1x=1/3
1、根号X+2乘以根号2X-1=根号3两边都平方得(X+2)(2X-1)=3整理得(2x+5)(x-1)=0x=-5/2或x=1因为x+2>=0,2x-1>=0,即想>=1/2所以x=12、(根号X+
2x^3+(1-√5)x^2-2√5x-√5+5=0,解得x1=(√5-1)/2,x2,3=土5^(1/4).
[x+2√(x-1)]=[√(x-1)+1]^2[x-2√(x-1)]=[√(x-1)-1]^2x-1>=0x>=1y=√[x+2√(x-1)]+√[x-2√(x-1)]=√(x-1)+1+|√(x-
因为根号(-x^2)有意义,则x=0所以答案为1-4+0+2=-1
(1)根号x+8+根号x-6=根号3-x+根号1由题意得x+8>=0,x-6>=0,3-x>=0所以无解(2)(x²+x)²+根号x²-1=0由题意得(x²+x
x²+(2根号3-1)x+3-根号3=0x²-(2√3-1)x+√3(√3-1)=0(x-√3)(x-√3+1)=0x=√3x=√3-1