用因式分解法解9(x-1)2=(2x+1)
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用因式分解法解9(x-1)2=(2x+1)
![用因式分解法解9(x-1)2=(2x+1)](/uploads/image/z/905407-7-7.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A39%28x-1%292%3D%282x%2B1%29)
9(x-1)^2=(2x+1)^2
9(x-1)^2-(2x+1)^2=0
[3(x-1)+(2x+1)][3(x-1)-(2x+1)]=0
(5x-2)(x-4)=0
5x-2=0 x-4=0
x1=2/5 x2=4
9(x-1)^2-(2x+1)^2=0
[3(x-1)+(2x+1)][3(x-1)-(2x+1)]=0
(5x-2)(x-4)=0
5x-2=0 x-4=0
x1=2/5 x2=4