题如图
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题如图
![](http://img.wesiedu.com/upload/2/cd/2cd3ba9b730614796f5acc11d3104e00.jpg)
![](http://img.wesiedu.com/upload/2/cd/2cd3ba9b730614796f5acc11d3104e00.jpg)
![题如图](/uploads/image/z/8858987-35-7.jpg?t=%E9%A2%98%E5%A6%82%E5%9B%BE)
这是一题考察白色沉淀硫酸钡在加了酸也不会再溶解,而碳酸钡沉淀了加了 酸沉淀就会溶解.
所以减少到的沉淀就只剩硫酸钡,m(BaSO4)=4.66g
Na2CO3 + BaCl2 = 2NaCl + BaCO3
106 207
y 9.85g
y = 106 × 9.85 g∕ 207 = 5.04g
Na2SO4 + BaCl2 = 2NaCl + BaSO4
193 233
x 4.66g
x = 4.66g × 193 ∕ 233 = 3.86 g
C(Na2CO3)= 5.04 / 106 / 100 / 1000 =0.5mol/l
C(Na2SO4)= 0.2mol/l
BaCO3+ 2HNO3 = 2H2O + Ba(NO3)2 + CO2
n(CO2)= 9.85 /207 = 0.048 mol
V(CO2) = 0.048×22.4= 1.0752 l
所以减少到的沉淀就只剩硫酸钡,m(BaSO4)=4.66g
Na2CO3 + BaCl2 = 2NaCl + BaCO3
106 207
y 9.85g
y = 106 × 9.85 g∕ 207 = 5.04g
Na2SO4 + BaCl2 = 2NaCl + BaSO4
193 233
x 4.66g
x = 4.66g × 193 ∕ 233 = 3.86 g
C(Na2CO3)= 5.04 / 106 / 100 / 1000 =0.5mol/l
C(Na2SO4)= 0.2mol/l
BaCO3+ 2HNO3 = 2H2O + Ba(NO3)2 + CO2
n(CO2)= 9.85 /207 = 0.048 mol
V(CO2) = 0.048×22.4= 1.0752 l