已知α,β∈(π/3,5π/6),若sin(α+π/6)=4/5,cos(β-5π/6)=5/13,则sin(α-β)=
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已知α,β∈(π/3,5π/6),若sin(α+π/6)=4/5,cos(β-5π/6)=5/13,则sin(α-β)=?
![已知α,β∈(π/3,5π/6),若sin(α+π/6)=4/5,cos(β-5π/6)=5/13,则sin(α-β)=](/uploads/image/z/8858565-45-5.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%2C%CE%B2%E2%88%88%EF%BC%88%CF%80%2F3%2C5%CF%80%2F6%29%2C%E8%8B%A5sin%EF%BC%88%CE%B1%2B%CF%80%2F6%EF%BC%89%3D4%2F5%2Ccos%EF%BC%88%CE%B2-5%CF%80%2F6%EF%BC%89%3D5%2F13%2C%E5%88%99sin%EF%BC%88%CE%B1-%CE%B2%EF%BC%89%3D)
∵α,β∈(π/3,5π/6)
==>π/2
==>π/2
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