若x^2-3x=1,则x^2y-3xy-y
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若x^2-3x=1,则x^2y-3xy-y
![若x^2-3x=1,则x^2y-3xy-y](/uploads/image/z/8572010-50-0.jpg?t=%E8%8B%A5x%5E2-3x%3D1%2C%E5%88%99x%5E2y-3xy-y)
解析:
若x²-3x=1,那么:
x²y-3xy-y
=y(x²-3x-1)
=y(1-1)
=0
若x²-3x=1,那么:
x²y-3xy-y
=y(x²-3x-1)
=y(1-1)
=0
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