设x,y为正数,且满足x²-2xy-y²=0,求x-y\x+y的值.
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设x,y为正数,且满足x²-2xy-y²=0,求x-y\x+y的值.
若分解x²-x+m得到两个因式x-2与x-n,求m与n的值。
若分解x²-x+m得到两个因式x-2与x-n,求m与n的值。
![设x,y为正数,且满足x²-2xy-y²=0,求x-y\x+y的值.](/uploads/image/z/8570563-43-3.jpg?t=%E8%AE%BEx%2Cy%E4%B8%BA%E6%AD%A3%E6%95%B0%2C%E4%B8%94%E6%BB%A1%E8%B6%B3x%26%23178%3B-2xy-y%26%23178%3B%3D0%2C%E6%B1%82x-y%5Cx%2By%E7%9A%84%E5%80%BC.)
x^2-2xy-y^2=0
x^2-2xy+y^2=2y^2
(x-y)^2=2y^2
|x-y|=根号2 Y
二边同除以Y得到:|X/Y-1|=根号2
即X/Y=1(+/-)根号2
(X-Y)/(X+Y)=(X/Y-1)/(X/Y+1)
(1)X/Y=1+根号2,原式=(1+根号2-1)/(1+根号2+1)=根号2/(2+根号2)=根号2*(2-根号2)/2=根号2-1
(2)X/Y=1-根号2,原式=(1-根号2-1)/(1-根号2+1)=[-根号2]/(2-根号2)=-根号2(2+根号2)/2=-根号2-1
再问: 若分解x²-x+m得到两个因式x-2与x-n,求m与n的值。
再答: x^2-x+m=(x-2)(x-n)=x^2-(2+n)x+2n 2+n=1 m=2n n=-1,m=-2
x^2-2xy+y^2=2y^2
(x-y)^2=2y^2
|x-y|=根号2 Y
二边同除以Y得到:|X/Y-1|=根号2
即X/Y=1(+/-)根号2
(X-Y)/(X+Y)=(X/Y-1)/(X/Y+1)
(1)X/Y=1+根号2,原式=(1+根号2-1)/(1+根号2+1)=根号2/(2+根号2)=根号2*(2-根号2)/2=根号2-1
(2)X/Y=1-根号2,原式=(1-根号2-1)/(1-根号2+1)=[-根号2]/(2-根号2)=-根号2(2+根号2)/2=-根号2-1
再问: 若分解x²-x+m得到两个因式x-2与x-n,求m与n的值。
再答: x^2-x+m=(x-2)(x-n)=x^2-(2+n)x+2n 2+n=1 m=2n n=-1,m=-2
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