3x²y+xy²-[2xy²-4x²y+(x²y-2xy²)
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3x²y+xy²-[2xy²-4x²y+(x²y-2xy²)],计算步骤是什么
急,
急,
原式=3x²y+xy²-2xy²+4x²y-x²y+2xy²
=3x²y+4²y-x²y+xy²-2xy²+2xy²
=6x²y+xy²
=xy(6x+y)
=3x²y+4²y-x²y+xy²-2xy²+2xy²
=6x²y+xy²
=xy(6x+y)
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
3x²y+xy²-[2xy²-4x²y+(x²y-2xy²)
计算 2xy[4x²y²-3y(xy+x²y)-xy²]
计算:(xy-x²)×x-y/xy
(2x²y-3xy²)-3(x²y-2xy²)+2(x²y-4xy
x²/xy-x/y
-3(xy-2x²)-[y²-(5xy-4x²)+2xy]
计算:x²+2xy+y²/xy-y².x²-2xy+y²/xy+y
化简4xy-3y²-3x²+xy-3xy-2x²+x²-2y²
先化简,再求值:{xy(x²-3y)+3xy²}(-2xy)+x³y²(2x-y
X²+2xy+y²/xy乘x²-2xy+y²/xy+y²=
-2y³+(3xy²-x²y)-2(xy²-y³)