解对数不等式log2 x>(log1/4 x)+3
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/05/14 05:31:26
解对数不等式
log2 x>(log1/4 x)+3
log2 x>(log1/4 x)+3
log1/4 x=lgx/lg(1/4)=lgx/lg2^(-2)=lgx/(-2lg2)=(-1/2)log2(x)
所以log2(x)>(-1/2)log2(x)+3
(3/2)log2(x)>3
log2(x)>2=log2(4)
底数2>1
所以log2(x)是增函数
所以x>4
所以log2(x)>(-1/2)log2(x)+3
(3/2)log2(x)>3
log2(x)>2=log2(4)
底数2>1
所以log2(x)是增函数
所以x>4
解对数不等式log2 x>(log1/4 x)+3
已知x满足不等式log1/2(x^2)≥log1/2(3x-2),求函数f(x)=log2(x/4)*log2(x/2)
已知x满足不等式log1/2x^2≥log1/2(3x-2),求函数f(x)=(log2^x/4)*(log2^x/2)
已知x满足不等式2(log1/2 x)^2+7log1/2 x+3≤0.f(x)=(log2 x/4)^2(log2 x
解不等式log2(x+1)+log1/4(x-1)〉log4(2x-1)
解不等式log1/2(3-x)>=log2(x+3)-1
解不等式log1/2^(x+1) +log2^[(1/(6-x)] 大于log1/2^12
高一数学对数函数解不等式2(log1/2^x)^2+7log1/2^x+3≤0
已知x满足不等式:2(log1/2 x)²+7log1/2 x +3≤0,则函数f(x)=(log2 x/4)
已知x满足不等式?log1/2 x +3≤0求函数f(x)=(log2 x/4)(log2 x/2)的最值
【高二数学】解不等式log2 (x+1)+log1/4 (x-1)>log4(2x-1)
解不等式:log1/3(x²-3x-4)>log1/3(2x+10)