求和:Sn=1/(1+根号3)+1/(根号3+根号5)+...+1/(根号2n-1+根号2n+1)
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求和:Sn=1/(1+根号3)+1/(根号3+根号5)+...+1/(根号2n-1+根号2n+1)
![求和:Sn=1/(1+根号3)+1/(根号3+根号5)+...+1/(根号2n-1+根号2n+1)](/uploads/image/z/826242-42-2.jpg?t=%E6%B1%82%E5%92%8C%EF%BC%9ASn%3D1%2F%281%2B%E6%A0%B9%E5%8F%B73%29%2B1%2F%28%E6%A0%B9%E5%8F%B73%2B%E6%A0%B9%E5%8F%B75%29%2B...%2B1%2F%28%E6%A0%B9%E5%8F%B72n-1%2B%E6%A0%B9%E5%8F%B72n%2B1%29)
Sn=1/(1+根号3)+1/(根号3+根号5)+...+1/(根号2n-1+根号2n+1)
1/(根号2n-1+根号2n+1)=1/2[根号(2n+1)-根号(2n-1)]
所以:
sn=1/2{根号3-1+根号5-根号3+根号7-根号5+...+根号(2n+1)-根号(2n-1)}
=1/2{根号(2n+1)-1}
1/(根号2n-1+根号2n+1)=1/2[根号(2n+1)-根号(2n-1)]
所以:
sn=1/2{根号3-1+根号5-根号3+根号7-根号5+...+根号(2n+1)-根号(2n-1)}
=1/2{根号(2n+1)-1}
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