已知函数f(x)满足f(1)=1/4,f(x)+f(y)=4f(x+y/2)*f(x-y/2)则f(-2011)=?
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已知函数f(x)满足f(1)=1/4,f(x)+f(y)=4f(x+y/2)*f(x-y/2)则f(-2011)=?
f(x)=f(x+1)+f(x-1)
f(x+1)=f(x)+f(x+2)
上面两个式子联立,
f(x+2)=-f(x-1)
即f(x)=f(x+6)
f(2010)=f(0)
4f(1)f(0)=f(1-0)+f(1+0)
f(0)=2f(1)=1/2.
f(x+1)=f(x)+f(x+2)
上面两个式子联立,
f(x+2)=-f(x-1)
即f(x)=f(x+6)
f(2010)=f(0)
4f(1)f(0)=f(1-0)+f(1+0)
f(0)=2f(1)=1/2.
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