1/2+1/4+1/8+1/16+...+1/1024
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1/2+1/4+1/8+1/16+...+1/1024
1/2+1/4+1/8+1/16+...+1/1024为一个等比数列的和,
Sn=[A1(1-q^n)]/(1-q)
=1/2(1-1/2^10) /1- 1/2
=1-1/2^10
=1023/1024
Sn=[A1(1-q^n)]/(1-q)
=1/2(1-1/2^10) /1- 1/2
=1-1/2^10
=1023/1024
1/2+1/4+1/8+1/16+...+1/1024
求和:1/2+1/4+1/8+1/16+1/32+1/64+.+1/1024=?
1/2+1/4+1/8+1/16+1/32……+1/1024
1/2+1/4+1/8+1/16+1/32+1/64+.+1024=?
2/1+4/1+8/1+16/1+32/1……+1024/1=
1/2+2/4+3/8+4/16+.+10/1024
计算:1/2+1/4+1/8+1/16+………+1/1024
1024+512+256+.+2+1+2/1+4/1+8/1+.512/1+1024/1
1-1/2-1/4-1/8-1/16-1/32-.-1/512-1/1024(简便计算)
1-1/2-1/4-1/8-1/16-1/32-1/64……-1/1024
1/2+1/4+1/8+1/1/16+.+1/312+1/1024+1/2048 简便计算
1+2+4+8+16+32+...+1024求解答,