sin^2(-a)cos(2pi+a)tan(-a-pi)化简
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/04/28 20:40:45
sin^2(-a)cos(2pi+a)tan(-a-pi)化简
sin^2(-a)cos(2pi+a)tan(-a-pi)
=sin^2acosa(-tana)
=-sin^2acosa(sina/cosa)
=-sin^3a
=sin^2acosa(-tana)
=-sin^2acosa(sina/cosa)
=-sin^3a
化简:sin(2pi-a)sin(pi+a)cos(-pi-a)/sin(3pi-a)cos(pi-a)
化简间sin(a-2pi)cos(a+pi)tan(a-99pi)cos(pi-a)sin(3pi-a)sin(-a-p
sin^2(-a)cos(2pi+a)tan(-a-pi)化简
sin^3(-a)cos(2pi+a)tan(-a-pi)化简
tana=2求sin(pi-a)cos(2pi-a)sin(-a+3pi/2)/tan(-a-pi)sin(-pi-a)
f(a)=sin(pi-a)cos(2pi-a)tan(-a+3pi/2)/cos(-pi-a) 求 f(-31pi/3
tan(5+a)=-2,且cos>0,则sin(-pi+a)=?/
cosa=2/3 a是第四象限角求sin(a-2Pi)+sin(-a-3Pi)cos(a-3Pi)/cos(Pi-a)-
tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ
tanθ=a,求[sin(pi/4+θ)/sin(pi/2-θ)]*tan2θ,
是否存在a属于(-pi/2,pi/2),b属于(0,pi),使等式sin(3Pi-a)=根号2cos(pi/2)-b),
三角形ABC中sin(2Pi-A)=-根号2cos(3Pi/2+B)根号3cos(2Pi-A)=根号2sin(Pi/2+