计算 -3(2x²-xy)+4(x²+xy-6)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/04/28 23:33:08
计算 -3(2x²-xy)+4(x²+xy-6)
-8m²-【4m-2m²-(3m-m²-7)-8】
-8m²-【4m-2m²-(3m-m²-7)-8】
-3(2x²-xy)+4(x²+xy-6)
=-6x²+3xy+4x²+4xy-24
=-2x²+7xy-24
-8m²-【4m-2m²-(3m-m²-7)-8】
=-8m²-4m+2m²+3m-m²-7+8
=-7m²-m+1
=-6x²+3xy+4x²+4xy-24
=-2x²+7xy-24
-8m²-【4m-2m²-(3m-m²-7)-8】
=-8m²-4m+2m²+3m-m²-7+8
=-7m²-m+1
计算 -3(2x²-xy)+4(x²+xy-6)
-3(2x²-xy)+4(x²+xy-6)
计算:(xy-x²)×x-y/xy
计算 2xy[4x²y²-3y(xy+x²y)-xy²]
计算18(4x²-xy)-19(4x²-xy)+(4x²-xy-1),
-3(xy-2x²)-[y²-(5xy-4x²)+2xy]
计算x²y³-2x(4xy³)
(-x²+2xy-y的平方)-2(xy—3x²)+3(2y的平方-xy) 计算.
计算:(-7x²y)(2x²y-3xy³+xy)
计算:2x+2y分之3y + x²+xy分之2xy
2x²y+{2xy-[x²y-2(﹣3x²y+xy)]﹣4xy²} 计算
用公式计算(2y-3x)(4y²+6xy+9x²﹚