计算[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]
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计算[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]
![计算[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]](/uploads/image/z/6467491-19-1.jpg?t=%E8%AE%A1%E7%AE%97%5Bx%2F%EF%B9%99xy%2By%EF%B9%9A%5D%C2%B7%5B%EF%B9%99x%26%23178%3B%2Bx%EF%B9%9A%EF%BC%8Fx%26%23178%3By%5D)
[x/﹙xy+y﹚]·[﹙x²+x﹚/x²y]
=[x/﹙y(x+1﹚]·[x﹙x+1﹚/x²y]
=1/y(x+1)*(x+1)/y
=1/y²
如果本题有什么不明白可以追问,
=[x/﹙y(x+1﹚]·[x﹙x+1﹚/x²y]
=1/y(x+1)*(x+1)/y
=1/y²
如果本题有什么不明白可以追问,
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