a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/05/13 12:18:48
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)=?
2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)
=[(a-b)+(a-c)]/(a-b)(a-c)+[(b-c)+(b-a)]/(b-c)(b-a)+[(c-a)+(c-b)]/(c-a)(c-b)
=1/(a-c)+1/(a-b)+1/(b-a)+1/(b-c)+1/(c-b)+1/(c-a)
=[1/(a-c)+1/(c-a)]+[1/(a-b)+1/(b-a)]+[1/(b-c)+1/(b-c)]
=0+0+0
=0
=[(a-b)+(a-c)]/(a-b)(a-c)+[(b-c)+(b-a)]/(b-c)(b-a)+[(c-a)+(c-b)]/(c-a)(c-b)
=1/(a-c)+1/(a-b)+1/(b-a)+1/(b-c)+1/(c-b)+1/(c-a)
=[1/(a-c)+1/(c-a)]+[1/(a-b)+1/(b-a)]+[1/(b-c)+1/(b-c)]
=0+0+0
=0
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(
(a+b)/(a-b)=(b+c)/2(b-c)=(c+a)/3(c-a),abc互不相等,证8a+9b+5c=o
行列式证明|b+c c+a a+b| | a b c||a+b b+c c+a| = 2 |c a b||c+a a+b
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
计算(a-b)(a-c)/(a+b-2c)(a+c-2b)+(b-c)(b-a)/(b+c-2a)(b+a-2c)+(c
计算a(b+c-a)^2+b(c+a-b)^2+c(a+b-c)^2+(b+c-a)(c+a-b)(a+b-c)
化简:2a-b-c/(a-b)(a-c) + 2b-a-c/(b-c)(b-a) + 2c-a-b/(c-b)(c-a)
化简(2a-b-c)/(a+b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-b)(c-a
初二分式的加减法2a-b-c/(a-b)(a-c)+ 2b-c-a/(b-c)(b-a)+ 2c-b-a/(c-b)(c
化简:(2a-b-c)/(a-b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-a)(c-
|a-b|+|a+c|-|b-c|+|2c|
|a-b|+|a+c|-|b-c|+|2c|怎么化简啊?