简算:2000-1997+1994-1991+1988-1985···+14-11+8-5
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简算:2000-1997+1994-1991+1988-1985···+14-11+8-5
一共有:[(2000-5)/3+1]/2=333组数,每一组的差=3
(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)
=3+3+3……+3共333个3相加,故:(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)=3*333=999
望君采纳,谢谢~
(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)
=3+3+3……+3共333个3相加,故:(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)=3*333=999
望君采纳,谢谢~
简算:2000-1997+1994-1991+1988-1985···+14-11+8-5
巧算:2000-1997+1994-1991+1988-1985+1982-1979+...+14-11+8-5+2
2000-1997+1994-1991+1988-1985+1982...+14-11+8-5+2
还要算出.是多少2000-1997+1994-1991+1988-1985+1952-1979+...+14-11+8-
2000-1997+1994-1991+1998-1985+1982-1979+...+14-11+8-5+2=( )简
2002+2000-1997+1994-1991+1988-……+14-11+8-5+2 =2002
简便计算1988-1985+1982-1979+······ +14-11+8-5=
2000-1997+1994-1991+1998-1995+1982-1979+...+14-11+8-5+2
计算2000-1997+1994-1991+1998-1995+1982-1979+~+14-11+8-5+2
求(2+5+8······+2000)-(1+4+7······+1999)的值.【简算】
2+5+8+11+14+······98+101的简便计算
2000-1999+1998-1997+1996-1995+1994-1993+······+4-3+2-1咋做?