刚刚那题倒数第二步看不懂?
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刚刚那题倒数第二步看不懂?
哪个题
给个链接
再问: =∫xdx-∫x/(x²+1) dx =x-1/2∫d(x²+1)/(x²+1) =x-1/2ln(x²+1)+C
再答: 哦,对不起,错了 ∫xdx=x =x²/2 ∫x/(x²+1) dx =∫1/2dx²/(x²+1) =1/2∫d(x²+1)/(x²+1) =1/2*ln(x²+1) 所以=x²/2+1/2*ln(x²+1)+C
给个链接
再问: =∫xdx-∫x/(x²+1) dx =x-1/2∫d(x²+1)/(x²+1) =x-1/2ln(x²+1)+C
再答: 哦,对不起,错了 ∫xdx=x =x²/2 ∫x/(x²+1) dx =∫1/2dx²/(x²+1) =1/2∫d(x²+1)/(x²+1) =1/2*ln(x²+1) 所以=x²/2+1/2*ln(x²+1)+C