[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/05/05 02:32:11
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
=[2sin50°*sin80°+sin10°*cos10°(cos10°+√3sin10°)/cos10°]*√2(sin80°)
=[2sin50°*sin80°+2sin10°(1/2cos10°+√3/2sin10°)]*√2(sin80°)
=[2sin50°*sin80°+2sin10°sin(30°+10°)]*√2(sin80°)
=[2sin50°*sin80°+2sin10°sin40°]*√2(sin80°)
=[2sin50°*cos10°+2sin10°cos50°]*√2(sin80°)
=2[sin60°]*√2(sin80°)
=√6sin80°
=[2sin50°*sin80°+sin10°*cos10°(cos10°+√3sin10°)/cos10°]*√2(sin80°)
=[2sin50°*sin80°+2sin10°(1/2cos10°+√3/2sin10°)]*√2(sin80°)
=[2sin50°*sin80°+2sin10°sin(30°+10°)]*√2(sin80°)
=[2sin50°*sin80°+2sin10°sin40°]*√2(sin80°)
=[2sin50°*cos10°+2sin10°cos50°]*√2(sin80°)
=2[sin60°]*√2(sin80°)
=√6sin80°
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
求值:[2sin50°+sin80°(1+√3tan10°)]/√2cos5°
化简【2sin50°+sin10°(1+根号3tan10°)】乘根号下2(sin80°的平方)
化简【2sin50°+sin80°(1+√3tan10°)】/cos5°
化简[2sin50°+sin10°(1+根号三tan10°)]*根号[2(sin80°)平方]拜托了各位
请问这个题怎么解?sin50°+sin10°(1+根号3*tan10°)根号下2*sin80°平方
[2sin50+sin10(1+根号3tan10)]sin80
求【2sin50度+sin10度(1+根号3tan10度)】sin80度的值
1/sin10°-√3/sin80°