(lg根号下27+lg8-lg根号下1000)/(1/2lg0.3+lg2)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/04/28 15:27:55
(lg根号下27+lg8-lg根号下1000)/(1/2lg0.3+lg2)
(lg根号下27+lg8-lg根号下1000)/(1/2lg0.3+lg2)
=(lg27^1/2+lg8-lg1000^1/2)/[1/2lg(3/10)+lg2]
=(1/2*lg27+lg8-1/2*lg1000)/[1/2*(lg3-lg10)+lg2]
=(1/2*lg3^3+lg2^3-1/2*lg10^3)/[1/2*(lg3-1)+lg2]
=(3/2*lg3+3lg2-3/2)/(1/2*lg3-1+lg2)
=3*(1/2*lg3-1+lg2)/(1/2*lg3-1+lg2)
=3
=(lg27^1/2+lg8-lg1000^1/2)/[1/2lg(3/10)+lg2]
=(1/2*lg27+lg8-1/2*lg1000)/[1/2*(lg3-lg10)+lg2]
=(1/2*lg3^3+lg2^3-1/2*lg10^3)/[1/2*(lg3-1)+lg2]
=(3/2*lg3+3lg2-3/2)/(1/2*lg3-1+lg2)
=3*(1/2*lg3-1+lg2)/(1/2*lg3-1+lg2)
=3
(lg根号下27+lg8-lg根号下1000)/(1/2lg0.3+lg2)
根号下{(lg3)平方-lg9+1}乘以(lg根号下27+lg8-lg根号下1000)再整体除以lg0.3乘以lg1.2
化简:(1)4lg2+3lg5-lg五分之一,(2)(lg根号下27+lg8-lg根号下1000)比上(lg1.2)
【根号(lg的平方3-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
lg5(lg8+lg1000)+(lg2^根号3)^2+lg(1/6)+lg0.06
【根号(lg3的平方-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
急(lg根号下27+lg8-lg根号下1000)\lg1.2=(3/2lg3+3lg2-3/2)/lg1.2然后呢
(lg根号27+lg8-3lg根号10)/lg3+2lg2-1
【根号lg9-lg9+lg10×(lg根号27+lg8-lg根号1000)】÷(lg0.3)(lg1.2)
lg5*lg800+lg根号下32/1.25+(lg2^根号3)^2-lg0.00032
(lg8+lg1000)lg5+3(lg2)^2+lg^-1+lg0.006
计算:(lg根号下27+lg8-lg根号下1000)\lg1.2