计算i-2根号3/(1+2根号3i)+(5+i^19)-(1+i/根号2)^22
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:综合作业 时间:2024/06/13 19:30:45
计算i-2根号3/(1+2根号3i)+(5+i^19)-(1+i/根号2)^22
![计算i-2根号3/(1+2根号3i)+(5+i^19)-(1+i/根号2)^22](/uploads/image/z/4640756-68-6.jpg?t=%E8%AE%A1%E7%AE%97i-2%E6%A0%B9%E5%8F%B73%2F%281%2B2%E6%A0%B9%E5%8F%B73i%29%2B%285%2Bi%5E19%29-%281%2Bi%2F%E6%A0%B9%E5%8F%B72%29%5E22)
i-2√3/(1+2√3i)+(5+i^19)-(1+i/√2)^2=i-(2√3)(1-2√3i)/13+5-i-(1+i-1/4)
=i-(2√3/13-12i/13)+5-i-3/4-i=17/4-2√3/13-(1/13)i
=i-(2√3/13-12i/13)+5-i-3/4-i=17/4-2√3/13-(1/13)i
计算i-2根号3/(1+2根号3i)+(5+i^19)-(1+i/根号2)^22
计算(1+i/1-i)^6+(根号2+根号3i/根号3-根号2i)的值
计算(2+2i/根号3-i)^7-(2-2i/1+根号3i)^7
计算[(2+2i)/(根号3-i)]^7-[(2-2i)/(1+根号3i)^7
计算:(2+2i)^2/(1-根号3i)^5
复数计算:(1/2+(根号3/2i))^5+(-1/2+(根号3/2i))^3
(1+根号3i)^2/根号3-i=
计算:(-2根号3 +i)/(1+2根号3i) +(根号2/1-i)^2010的值为?
计算i(1-根号3i
计算(根号3/2i-1/2)(-1/2+根号3/2i)
(-3)^0-根号27+I1-根号2I+根号3+根号2分之1
(2+2i)^4/(1-根号3i)^5复数的计算