x³y-2x²y²+xy³
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/18 01:28:05
x³y-2x²y²+xy³
![x³y-2x²y²+xy³](/uploads/image/z/4599514-10-4.jpg?t=x%26%23179%3By-2x%26%23178%3By%26%23178%3B%2Bxy%26%23179%3B)
x³y-2x²y²+xy³
=xy(x²-2xy+y²)
=xy(x-y)²
=xy(x²-2xy+y²)
=xy(x-y)²
[-xy/(x-y)²]²×(y²-xy/x)³
x³y-2x²y²+xy³
先化简,再求值:{xy(x²-3y)+3xy²}(-2xy)+x³y²(2x-y
化简x-y分之x + x³-2x²y+xy²分之y³ ÷ y²-x
2x+y=0,求4x²+2xy(x+y)+y³
因式分解x的5次方y-x³y+2x²y-xy
-x²y+2xy²-y³ 因式分解
多项式因式分解 1,(x-y)³-(x-y)²(x+y) 2,x(x²-xy)-(4x
-2y³+(3xy²-x²y)-2(xy²-y³)
-x³y³-x²y²+xy
x²-2xy+y²分之x²+2xy-3y³如何因式分解
因式分解:(x+y)³+2xy-2x²y-2xy²-1