求1/ln(x+1)的导数
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求1/ln(x+1)的导数
1/ln(x+1)的导数
=-1/(ln(x+1))²* (ln(x+1))'
=-1/(ln(x+1))²* (1/(x+1))
=-1/[(x+1)(ln(x+1))²]
=-1/(ln(x+1))²* (ln(x+1))'
=-1/(ln(x+1))²* (1/(x+1))
=-1/[(x+1)(ln(x+1))²]