tan(nA/2)tan(nB/2)+tan(nB/2)tan(nC/2)+tan(nA/2)tan(nC/2)=1(n
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tan(nA/2)tan(nB/2)+tan(nB/2)tan(nC/2)+tan(nA/2)tan(nC/2)=1(n为奇数)
![tan(nA/2)tan(nB/2)+tan(nB/2)tan(nC/2)+tan(nA/2)tan(nC/2)=1(n](/uploads/image/z/3996899-35-9.jpg?t=tan%28nA%2F2%29tan%28nB%2F2%29%2Btan%28nB%2F2%29tan%28nC%2F2%29%2Btan%28nA%2F2%29tan%28nC%2F2%29%3D1%EF%BC%88n)
求什么?
证明 tan(nA/2)tan(nB/2)+tan(nB/2)tan(nC/2)+tan(nA/2)tan(nC/2)=
tan(nA/2)tan(nB/2)+tan(nB/2)tan(nC/2)+tan(nA/2)tan(nC/2)=1(n
2(tan a+tan b)
三角函数证明题:tan(kA/2)tan(kB/2)+tan(kB/2)tan(kC/2)+tan(kA/2)tan(k
tanα=2tanα吗
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sin2α=2tanα/(1+tan²α) ,cos2α=(1-tan²α)/(1+tan²
证明..!tanθ/2-1/(tanθ/2)=-2/tanθ
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