若有理数X、Y满足x²-4x+y²+6y+13=0,求xy的值
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若有理数X、Y满足x²-4x+y²+6y+13=0,求xy的值
x²-4x+y²+6y+13=0;
(x-2)²+(y+3)²=0;
x=2;y=-3;
xy=-6;
(x-2)²+(y+3)²=0;
x=2;y=-3;
xy=-6;
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