(x^2-x)^2+3x(x-1)-54 、 (m^2+3m)^2-8(m^2+3m)+16 、 (c^2-a^2-b^
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(x^2-x)^2+3x(x-1)-54 、 (m^2+3m)^2-8(m^2+3m)+16 、 (c^2-a^2-b^2)^2-4a^2b^2 这三题 因式分解
(x^2-x)^2+3x(x-1)-54
=[x(x-1)]²+3x(x-1)-54
=[x(x-1)+9][x(x-1)-6]
=(x²-x-9)(x²-x-6)
=(x²-x-9)(x-3)(x+2)
(m^2+3m)^2-8(m^2+3m)+16
=(m^2+3m-4)²
=(m+4)²(m-1)²
(c^2-a^2-b^2)^2-4a^2b^2
=(c^2-a^2-b^2+2ab)(c^2-a^2-b^2-2ab)
=[c²-(a²-2ab+b²)][c²-(a²+2ab+b²)]
=[c²-(a-b)²][c²-(a+b)²]
=(c+a-b)(c-a+b)(c+a+b)(c-a-b)
=[x(x-1)]²+3x(x-1)-54
=[x(x-1)+9][x(x-1)-6]
=(x²-x-9)(x²-x-6)
=(x²-x-9)(x-3)(x+2)
(m^2+3m)^2-8(m^2+3m)+16
=(m^2+3m-4)²
=(m+4)²(m-1)²
(c^2-a^2-b^2)^2-4a^2b^2
=(c^2-a^2-b^2+2ab)(c^2-a^2-b^2-2ab)
=[c²-(a²-2ab+b²)][c²-(a²+2ab+b²)]
=[c²-(a-b)²][c²-(a+b)²]
=(c+a-b)(c-a+b)(c+a+b)(c-a-b)
(x^2-x)^2+3x(x-1)-54 、 (m^2+3m)^2-8(m^2+3m)+16 、 (c^2-a^2-b^
集合A={x|x=3m-2,m∈Z},B={x|x=3m+1,m∈Z},C={x|x=6m+1,m∈Z},则集合A,B,
若集合A={X/X=3m-2,m属于Z},B=3m+1,m属于Z},C={x/x=6m+1,m属于Z},则集合A,B,C
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已知函数Y=ln{(2-x)[x-(3m+1)]}的定义域为集合A,集合B={x︳(x-(m^2+1))/(x-m)
x^(3)*x^(2m +1)*x^(m)=x^(31) 求m的值
A={x|x²-2x-8≤0} B={x|x²-(2m-3)x+m²-3m≤0}
计算x^3m/(x^m-1)-x^2m/(x^m+1)-1/(x^m-1)+1(x^m+1)
已知恒等式x^4+ax^3+bx^2+cx+24=(x+1)(x+2)(x+3)(x+m),a+b+c+m=
设集合a={m,2m,3m},b={x/1
已知实数x,y,m满足根号x+2+|3x+y+m|=0,且y为负数,则m的取值范围是() a.m>6 b.m<6 c.m
探索:如果X+1分之3X-2=3+ X+1分之M,则M等于_-5__ 如果x+c分之ax+b=a+ x+c分之M,则M等