2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/24 05:25:37
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
![2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)](/uploads/image/z/26003-11-3.jpg?t=2001%C3%97%EF%BC%881%2F8-1%2F2009%EF%BC%89%2B8%C3%97%EF%BC%881%2F2000-1%2F2009%EF%BC%89-2009%C3%97%281%2F8%2B1%2F2001%29)
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
=(2001-2009)/8-(2001+8)/2009+8/2000-2009/2001
=-1-1-1+8/2000-8/2001
=-3+1/500250
=-2又500249/500250
=(2001-2009)/8-(2001+8)/2009+8/2000-2009/2001
=-1-1-1+8/2000-8/2001
=-3+1/500250
=-2又500249/500250
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
计算2001*(1/8-1/2009) 8*(1/2001-1/2009) 2009*(1/8-1/2001)
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8等于多少?
求2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8的简便方
用简便方法 2001×(8分之1-2009分之1)+8×(2001分之1-2009分之1)-2009×(8分之1+200
2001乘[8分之1减2009分之1]加8乘[2001分之1减2009分之1]减2009乘[8分之1加2001分之1﹞加
2001×(八分之一-2009分之一)+8×(2001分之一-2009分之一)-2009×(8分之一+2001分之一)+
2000分之1+2001分之1+2002分之1+.+2009分之1分之1
1/2000+1/2001+1/2002+1/2009的倒数怎样求