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1的立方+3的立方+5的立方+……+(2n-1)的立方.(n属于N*)怎么求和?

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1的立方+3的立方+5的立方+……+(2n-1)的立方.(n属于N*)怎么求和?
1的立方+3的立方+5的立方+……+(2n-1)的立方.(n属于N*)怎么求和?
i=1到2n
∑i^3
=∑(i+1)i(i-1)+∑i
=6∑C(3,i+1)+∑C(1,i)
=6C(4,2n+2)+C(2,2n+1)
=(2n+2)(2n+1)2n(2n-1)/4+(2n+1)2n/2
=[n(2n+1)]^2
i=1到n
∑(2i)^3
= 8∑(i)^3
=8∑(i+1)i(i-1)+8∑i
=48∑C(3,i+1)+8∑C(1,i)
=48C(4,n+2)+8C(2,n+1)
=8(n+2)(n+1)n(n-1)/4+8(n+1)n/2
=8[n(n+1)/2]^2
[n(2n+1)]^2-8[n(n+1)/2]^2=你要的