a^4-(a-b)(a+b)(a^2-b^2)=?(x-1)^2+(y+2)^2-(x+y)(x-y)=?97×99×1
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a^4-(a-b)(a+b)(a^2-b^2)=?(x-1)^2+(y+2)^2-(x+y)(x-y)=?97×99×101×103=?
初二上册练习题,我在预习,拿不准,请求大师指点
初二上册练习题,我在预习,拿不准,请求大师指点
![a^4-(a-b)(a+b)(a^2-b^2)=?(x-1)^2+(y+2)^2-(x+y)(x-y)=?97×99×1](/uploads/image/z/18312065-17-5.jpg?t=a%5E4-%28a-b%29%28a%2Bb%29%28a%5E2-b%5E2%29%3D%3F%28x-1%29%5E2%2B%28y%2B2%29%5E2-%28x%2By%29%28x-y%29%3D%3F97%C3%9799%C3%971)
a^4-(a-b)(a+b)(a^2-b^2)=a^4-(a^2-b^2)^2=-b^4+2a^2b^2
(x-1)^2+(y+2)^2-(x+y)(x-y)=x^2-2x+1+y^2+4y+4-x^2+y^2=-2x+2y^2+4y+5
97×99×101×103==(100+3)(100-3)(100+1)(100-1)=(10000-9)(10000-1)
=99900009
望采纳
(x-1)^2+(y+2)^2-(x+y)(x-y)=x^2-2x+1+y^2+4y+4-x^2+y^2=-2x+2y^2+4y+5
97×99×101×103==(100+3)(100-3)(100+1)(100-1)=(10000-9)(10000-1)
=99900009
望采纳
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