-4a^2x^2+12ax-9=?4(x+y)^2-12(x+y)+9=?x^2+2x(y-z)+(z-y)^2=?(1
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/17 22:08:02
-4a^2x^2+12ax-9=?4(x+y)^2-12(x+y)+9=?x^2+2x(y-z)+(z-y)^2=?(1/8a^3b^2c-4a^2b^3)(2a^2bc)^3=?
(a-1/2b)^2+(a+1/2b)^2=?
(a-1/2b)^2+(a+1/2b)^2=?
1、-4a²x²+12ax-9=-(4a²x²-12ax+9)=-(2ax+3)²
2、4(x+y)²-12(x+y)+9=[2(x+y)-3]²=(2x+2y-3)²
3、x²+2x(y-z)+(z-y)²=x²+2x(y-z)+(y-z)²=(x+y-z)²
4、(1/8a³b²c-4a²b³)(2a²bc)³
=1/8a²b²(ac-32b)(2a²bc)³
2、4(x+y)²-12(x+y)+9=[2(x+y)-3]²=(2x+2y-3)²
3、x²+2x(y-z)+(z-y)²=x²+2x(y-z)+(y-z)²=(x+y-z)²
4、(1/8a³b²c-4a²b³)(2a²bc)³
=1/8a²b²(ac-32b)(2a²bc)³
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
解方程组1、4x+9y=12,3y-2z=1,2x+6z=32、3x-y+2z=3,2x+y-3z=11,x+y+z=1
三元一次方程组(1)x-2y=-9 y-z=3 2z+x=47 (2)3x-y+z=4 2x+3y-z=12 x+y+z
x-2y=-9 3x-y+z=4 y-z=3 2x+3y-z=12 2z+x=47 x+y+z=6 这是七年级下册数学1
(x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z,
1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-
解三元一次方程组 {2x+y+3z=1 y-2z=4 3x+y=9 {2x+y+z=9 y-2z=-12 3x+y=7
解三元一次方程组:{x+y+z=4 2x+y+3z=9 x+3y+2z=14 {3x+y-z=7 x+2y+2z=12
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}