化简求值[(x+y)²-(x-y)²+4x²y²]÷4xy,x=(√2)°,y=
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化简求值[(x+y)²-(x-y)²+4x²y²]÷4xy,x=(√2)°,y=2
那个°是零次方
那个°是零次方
原式=(x²+2xy+y²-x²+2xy-y²+4x²y²)÷4xy
=(4xy+4x²y²)÷4xy
=1+xy
当x=1,y=2时,
原式=1+2=3
=(4xy+4x²y²)÷4xy
=1+xy
当x=1,y=2时,
原式=1+2=3
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