计算题 (1)-x²·﹙-x﹚² (2)﹙x-2﹚﹙x+3﹚
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计算题 (1)-x²·﹙-x﹚² (2)﹙x-2﹚﹙x+3﹚
1.计算题 (1)-x²·﹙-x﹚² (2)﹙x-2﹚﹙x+3﹚ (3)﹙a-2b+3c﹚﹙a+2b-3c﹚ ﹙4﹚﹙a+1/2﹚²·﹙a²+1/4﹚²·﹙a-1/2﹚²
2.若x²+2x+y²-6y+10=0,求x,y的值.
1.计算题 (1)-x²·﹙-x﹚² (2)﹙x-2﹚﹙x+3﹚ (3)﹙a-2b+3c﹚﹙a+2b-3c﹚ ﹙4﹚﹙a+1/2﹚²·﹙a²+1/4﹚²·﹙a-1/2﹚²
2.若x²+2x+y²-6y+10=0,求x,y的值.
1.计算题
(1)-x²·﹙-x﹚²=-x^4
(2)﹙x-2﹚﹙x+3﹚ = x²+x-6
(3)﹙a-2b+3c﹚﹙a+2b-3c﹚
=a² -(2b-3c)²
=a²-4b²+12bc-9c²
﹙4﹚﹙a+1/2﹚²·﹙a²+1/4﹚²·﹙a-1/2﹚²
=﹙a²-1/4﹚²·﹙a²+1/4﹚²
=﹙a^4-1/16﹚²
=a^8-1/8a^4-1/256
2.若x²+2x+y²-6y+10=0,
则(x+1)²+(y-3)²=0
x+1=0 x=-1
y-3=0 y=3
(1)-x²·﹙-x﹚²=-x^4
(2)﹙x-2﹚﹙x+3﹚ = x²+x-6
(3)﹙a-2b+3c﹚﹙a+2b-3c﹚
=a² -(2b-3c)²
=a²-4b²+12bc-9c²
﹙4﹚﹙a+1/2﹚²·﹙a²+1/4﹚²·﹙a-1/2﹚²
=﹙a²-1/4﹚²·﹙a²+1/4﹚²
=﹙a^4-1/16﹚²
=a^8-1/8a^4-1/256
2.若x²+2x+y²-6y+10=0,
则(x+1)²+(y-3)²=0
x+1=0 x=-1
y-3=0 y=3
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