因式分解(xy-1)²+(x+y-2)(x+y-2y)怎么做哇?
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/06/14 12:26:52
因式分解(xy-1)²+(x+y-2)(x+y-2y)怎么做哇?
![因式分解(xy-1)²+(x+y-2)(x+y-2y)怎么做哇?](/uploads/image/z/1563937-25-7.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%28xy-1%29%26%23178%3B%2B%28x%2By-2%29%28x%2By-2y%29%E6%80%8E%E4%B9%88%E5%81%9A%E5%93%87%3F)
最后一项是否多了一个y?如果没有那个y,就应当是
(xy-1)²+(x+y-2)(x+y-2)
=(xy-1+x+y-2)(xy-1-x-y+2)
=(xy+x+y-3)(xy-x-y+1)
再问: 对不起啊,真的打错了正确的是:(xy-1)²+(x+y-2)(x+y-2xy)少了个x,帮忙解解。
再答: 原式 =x^2y^2-2xy+1+(x+y)^2-2(x+y)-2xy(x+y)+4xy =x^2y^2+2xy+1+(x+y)^2-2(x+y) =(xy+1)^2-2(x+y)+(x+y)^2 =(xy+1-x-y)^2
(xy-1)²+(x+y-2)(x+y-2)
=(xy-1+x+y-2)(xy-1-x-y+2)
=(xy+x+y-3)(xy-x-y+1)
再问: 对不起啊,真的打错了正确的是:(xy-1)²+(x+y-2)(x+y-2xy)少了个x,帮忙解解。
再答: 原式 =x^2y^2-2xy+1+(x+y)^2-2(x+y)-2xy(x+y)+4xy =x^2y^2+2xy+1+(x+y)^2-2(x+y) =(xy+1)^2-2(x+y)+(x+y)^2 =(xy+1-x-y)^2