计算:(1)log2748
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计算:
(1)log2
(1)log2
|
(1)log2
7
48+log212-
1
2log242-1
=log2(
7
48×12×
1
42×
1
2)
=log22−
3
2=-
3
2.
(2)0.027 −
1
3-(-
1
6)-2+2560.75+(
1
3−1)0-3-1
=0.3-1-36+64+1-
1
3
=32.
7
48+log212-
1
2log242-1
=log2(
7
48×12×
1
42×
1
2)
=log22−
3
2=-
3
2.
(2)0.027 −
1
3-(-
1
6)-2+2560.75+(
1
3−1)0-3-1
=0.3-1-36+64+1-
1
3
=32.