5x²-[x²-2x-2(x²-3x+1)]这道题的解?
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5x²-[x²-2x-2(x²-3x+1)]这道题的解?
![5x²-[x²-2x-2(x²-3x+1)]这道题的解?](/uploads/image/z/14904925-61-5.jpg?t=5x%26%23178%3B%EF%BC%8D%5Bx%26%23178%3B%EF%BC%8D2x%EF%BC%8D2%EF%BC%88x%26%23178%3B%EF%BC%8D3x%EF%BC%8B1%EF%BC%89%5D%E8%BF%99%E9%81%93%E9%A2%98%E7%9A%84%E8%A7%A3%3F)
5x²-[x²-2x-2(x²-3x+1)]
=5x²-(x²-2x-2x²+6x-2)
=5x²-(-x²+4x-2)
=5x²+x²-4x+2
=6x²-4x+2
=5x²-(x²-2x-2x²+6x-2)
=5x²-(-x²+4x-2)
=5x²+x²-4x+2
=6x²-4x+2
5x²-[x²-2x-2(x²-3x+1)]这道题的解?
x(2x-1)=-3x(x+1)+5x²+3
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