lim(n2+1/n+1-an-b)=0,求a,b
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lim(n2+1/n+1-an-b)=0,求a,b
n2+1/n+1:n方加1除以n+1
n2+1/n+1:n方加1除以n+1
![lim(n2+1/n+1-an-b)=0,求a,b](/uploads/image/z/1334545-25-5.jpg?t=lim%28n2%2B1%2Fn%2B1-an-b%29%3D0%2C%E6%B1%82a%2Cb)
lim是n->0?还是n->无穷啊?
如果是0:1-0-b=0,b=1.a任意.
如果是无穷:n-an-b=0,a=1,b=0
如果是0:1-0-b=0,b=1.a任意.
如果是无穷:n-an-b=0,a=1,b=0
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