化简lg[cos(2π-x)cot(3π/2-x)+1-2xin^2x/2]+lg[根号2cos(x-π/4)]-lg[
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化简lg[cos(2π-x)cot(3π/2-x)+1-2xin^2x/2]+lg[根号2cos(x-π/4)]-lg[1-sin(π+2x)]
请详细过程,谢谢!
请详细过程,谢谢!
![化简lg[cos(2π-x)cot(3π/2-x)+1-2xin^2x/2]+lg[根号2cos(x-π/4)]-lg[](/uploads/image/z/1247384-56-4.jpg?t=%E5%8C%96%E7%AE%80lg%5Bcos%EF%BC%882%CF%80-x%EF%BC%89cot%EF%BC%883%CF%80%2F2-x%29%2B1-2xin%5E2x%2F2%5D%2Blg%5B%E6%A0%B9%E5%8F%B72cos%28x-%CF%80%2F4%29%5D-lg%5B)
lg[(cosx*tanx)+cosx](cosx+sinx)/(1+sin2x)]
=lg[(sinx+cosx)(cosx+sinx)/(sinx+cosx)^2]
=lg1
=0
=lg[(sinx+cosx)(cosx+sinx)/(sinx+cosx)^2]
=lg1
=0
化简lg[cos(2π-x)cot(3π/2-x)+1-2xin^2x/2]+lg[根号2cos(x-π/4)]-lg[
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