根号下{[log2 (5)]^2-4log2(5)+4}+log2(1/5)
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根号下{[log2 (5)]^2-4log2(5)+4}+log2(1/5)
令a=log2(5)
则log2(1/5)=-log2(5)=-a
且5>2²,所以a>2
a-2>0
原式=√(a²-4a+4)-a
=√(a-2)²-a
=|a-2|-a
=a-2-a
=-2
则log2(1/5)=-log2(5)=-a
且5>2²,所以a>2
a-2>0
原式=√(a²-4a+4)-a
=√(a-2)²-a
=|a-2|-a
=a-2-a
=-2
根号下{[log2 (5)]^2-4log2(5)+4}+log2(1/5)
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