3/(a+1)-12/(a²-1)-6/(1-a)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/05/26 07:42:31
3/(a+1)-12/(a²-1)-6/(1-a)
3/﹙a+1﹚-12/﹙a²-1﹚-6/﹙1-a﹚
=﹙3a-3﹚/﹙a²-1﹚-12/﹙a²-1﹚+﹙6a+6﹚/﹙a²-1﹚
=﹙3a-3-12+6a+6﹚/﹙a²-1﹚
=9﹙a-1﹚/﹙a²-1﹚
=9/﹙a+1﹚.
=﹙3a-3﹚/﹙a²-1﹚-12/﹙a²-1﹚+﹙6a+6﹚/﹙a²-1﹚
=﹙3a-3-12+6a+6﹚/﹙a²-1﹚
=9﹙a-1﹚/﹙a²-1﹚
=9/﹙a+1﹚.
9-a²/a²+6a+9÷a²-3a/a+1/a
化简3a×a×a+12a×a-6a-12 a=根号7-1
因式分解:a^12+a^9+a^6+a^3+1
3/(a+1)-12/(a²-1)-6/(1-a)
2/9-3a,a-1/a²-3-2a,a/a²-5a+6。
(a 1)(a 2)(a 3)(a
计算:a²+9-6a分支2a²-4a-6/(4a+8)×4+3a-a²分支6+a-a
(1/4根号32a)+(6a根号a/18)-(3a²根号2/a)
计算(a+1)(a+2)(a+3)(a-6)
计算2a(a-3)^1-6a^2(3-a)-8a(a-3)
2a/3根号9a+6a根号a/4-a平方根号1/a,
a(a-1)(a-2)(a-3)(a-4)因式分解