设函数f(x)=cos(2x+π/3)+sin方x
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/05/15 01:26:43
设函数f(x)=cos(2x+π/3)+sin方x
1)求函数f(x)的最大值和最小正周期
2)设A、B、C为△ABC的三个内角,若cosB=1/3,f(C/2)=-1/4,且C为锐角,求sinA
1)求函数f(x)的最大值和最小正周期
2)设A、B、C为△ABC的三个内角,若cosB=1/3,f(C/2)=-1/4,且C为锐角,求sinA
f(x)=cos(2x+π/3)+sin²x
=cos2xcosπ/3-sin2xsinπ/3+[1-cos(2x)]/2
=1/2cos2x-√3/2sin2x+1/2-1/2cos2x
=-√3/2sin2x+1/2
当sin2x=-1时,最大值=(1+√3)/2
最小正周期=2π/2=π
f(C/2)=-√3/2sinC+1/2=-1/4
sinC=√3/2
∵C为锐角
C=π/3
cosC=1/2
∵cosB=1/3
∴sinB=2√2/3
sinA=sin(π-B-C)
=sin(B+C)
=sinBcosC+cosBsinC
=2√2/3×1/2+1/3×√3/2
=√2/3+√3/6
=cos2xcosπ/3-sin2xsinπ/3+[1-cos(2x)]/2
=1/2cos2x-√3/2sin2x+1/2-1/2cos2x
=-√3/2sin2x+1/2
当sin2x=-1时,最大值=(1+√3)/2
最小正周期=2π/2=π
f(C/2)=-√3/2sinC+1/2=-1/4
sinC=√3/2
∵C为锐角
C=π/3
cosC=1/2
∵cosB=1/3
∴sinB=2√2/3
sinA=sin(π-B-C)
=sin(B+C)
=sinBcosC+cosBsinC
=2√2/3×1/2+1/3×√3/2
=√2/3+√3/6
设函数f(x)=cos(2x+π/3)+sin方x
设函数f(X)=cos(2x+π/3)+sin方x.求函数f(x)的最大值和最小正周期
已知函数f(x)=cos(2x-π/3)+sin^2x-cos^2x,设函数g(x)=[f(x)]^2+f(x),求g(
设函数f(x)=cos(2x+π/3)+sin^2x-1/2
设函数f(x)=cos(2x+π/3)+sin^2 X
设函数f(x)=cos(2x+π/3)+sin^2x
急.设函数f(x)=cos(2x+π/3)+sin^2 X
1.设函数f(x)=cos(2x+π/3)+sin(平方)x
设函数f(x)=cos(2x+π/3)+sin²x
设函数f(x)=cos(2x+π/3)+sin²X
设函数f(x)=2+sin(3x+π/12)cos(x+π/6)+cos(3x+π/12)sin(x+π/6)
设函数f(x)=cos(2x+pai/3)+sin^2x