一道概率论简单题目求教
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一道概率论简单题目求教
A1次品,A2正品,B检定为次品,由贝叶斯公式
P(A1IB)=P(BIA1)P(A1)/[P(BIA1)P(A1)+P(BIA2)P(A2)]=0.99*0.04/[0.99*0.04+0.005*0.96]
=0.892
P(A1IB)=P(BIA1)P(A1)/[P(BIA1)P(A1)+P(BIA2)P(A2)]=0.99*0.04/[0.99*0.04+0.005*0.96]
=0.892