{3x 3y}-{3x 3y}
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[x(x2y2-xy)-y(x2+x3y)]÷3x2y,=(x3y2-x2y-x2y-x3y2)÷3x2y,=-2x2y÷3x2y,=-23.
原式=(x4-xy3)+(y4-x3y)+(3xy2-3x2y)=x(x3-y3)+y(y3-x3)+3xy(y-x)=(x3-y3)(x-y)-3xy(x-y)=(x-y)(x3-y3-3xy)=(
按字母x的升幂排列就把y看成系数y4-xy3+x2y2+3x3y
原式=4x29y2•27y364x3•4xy=34x2.故答案为34x2.
反应前XY均为0价,反应后化合价有变化,四氧化还原反应.提一句,4X2+Y2=X3Y+Y2去掉Y2的话是4X2=X3Y,这是不可能的,元素本身发生了变化,应该是核反应
5x5-15x3y-20xy2=5x(x^4-3x²y-4y²)=5x(x²-4y)(x²+y)3a2b2-17abxy+10x2y2=(3ab-2xy)(ab
解题思路:某项的字母指数和为该项的次数,常数项即为常数解题过程:解:最高项是-3,最高项系数是5和4,常数项是-2
原式=(x3y2-x2y-x2y+x3y2)÷3x2y=(2x3y2-2x2y)÷3x2y=23xy-23.
按x得降幂排列:x^4-4x^3y-x²y²+3xy^3-y^4按y得升幂排列:x^4-4x^3y-x²y²+3xy^3-y^4
多项式-3xy+5x3y-2x2y3+5的次数是5.最高次项系数是-2,常数项是5.故答案为:5,-2,5.
已知x+y=5,xy=3,代数式x3y-2x平方y平方+xy3=xy(x²-2xy+y²)=xy(x-y)²=3×[(x+y)²-4xy]=3×(25-12)=
∵|x+y+1|≥0,|xy-3|≥0|x+y+1|+|xy-3|=0,∴x+y+1=0,即x+y=-1xy=3xy3+x3y=xy(x²+y²)=yx[(x+y)²-2
多项式2-xy2-4x3y是四次三项式,其中3次项的系数是-1,故答案为:四、三,-1.
x3y+xy3=xy(x^2+y^2)=(√3-√2)(√3+√2)((√3-√2)^2)+(√3-√2)^2)=1*(3-2√6+2+3+2√6+2)=10
(1)原式=x2-(2y-3)2=x2-4y2+12y-9;(2)原式=4x6y2•(-2xy)-8x9y3÷(2x2)=-8x7y3-4x7y3=-12x7y3.
原式=[x3y2-x2y-x2y+x3y2]÷3x2y=(2x3y2-2x2y)÷3x2y=23xy-23;当x=3,y=-1时,原式=23×3×(-1)-23=-83.
(x-y)2=x2-2xy+y2=9,当x2+y2=13时,13-2xy=9,解得xy=2.当xy=2,x2+y2=13时,x3y-8x2y2+xy3=xy(x2-8xy+y2)=2×(13-8×2)
∵x+y=3,∴(x+y)2=9,即x2+y2+2xy=9①,又x2+y2-3xy=4②,①-②,得5xy=5,xy=1.∴x2+y2=4+3xy=7.∴x3y+xy3=xy(x2+y2)=7.故答案
x4-xy3-x3y-3x2y+3xy2+y4=(x4-xy3)+(y4-x3y)+(3xy2-3x2y)=x(x3-y3)+y(y3-x3)+3xy(y-x)=(x3-y3)(x-y)-3xy(x-
3x3y-12xy3,=3xy(x2-4y2),=3xy(x+2y)(x-2y).故答案为:3xy(x+2y)(x-2y).