x-100+250=2/3x怎么解

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x-100+250=2/3x怎么解
1X+2X+3X…+98X+99X+100X=50500X X等于多少?

1X+2X+3X…+98X+99X+100X=5050x=50500x=10

已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值

x^4+x^3+x^2+x+1=0,x^100+x^99+x^98+x^97+x^96=x^96(x^4+x^3+x^2+x+1)=x^96*0=0

先化简再求值(x+3x+5x+7x+.+101x)-(2x+4x+6x+...100x),其中x=51分之2

=x+(3x-2x)+(5x-4x)+……+(101x-100x)=x+x+……+x=51x=51×2/51=2

一道数学题:1/x-1+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-99)(x-100)

/>原式=1/(x-1)+[1/(x-2)-1/(x-1)]+[1/(x-3)-1/(x-2)]……+[1/(x-100)-1/(x-99)]=1/(x-1)-1/(x-1)+1/(x-2)-1/(x

2x+3x+4x+5x+x+6x+7x=100

2x+3x+4x+5x+x+6x+7x=10028x=100x=100/28x=25/7

x-2x+3x-4x+...+99x-100x=25

x-2x+3x-4x+...+99x-100x=25(1-2)x+(3-4)x+…+(99-100)x=25-x-x-…-x=25-50x=25x=-1/2

解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x)

2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99

(x+2x+3x+.100x )化简

(x+2x+3x+.100x)=(1+2+3...+100)x=100(100+1)x/2=5050x

12x+3x=18+27 11x+40=100-9 9x+30=90+6x 2.5x-x=6+1.5 2x+18=7x+

这都做不起啊再问:.......●︿●再问:告诉我第一题的做法就行了再答:有x的数字相加,等号右边相加,然后等号右边除以等号左边的数字就求出x了再问:谢谢,我一直对方程的做法不怎么了解。现在懂了。再问

x/(x-1) -1=3/(x-1)(x+2)

解由x/(x-1)-1=3/(x-1)(x+2)知两边乘以(x-1)(x+2)得x(x+2)-(x-1)(x+2)=3即x^2+2x-(x^2+x-2)=3即2x^2+x-1=0即(2x-1)(x+1

x^2-3x

答:x^2-3x

(x+3)(x-2)

令(x+3)(x-2)=0,解得:X=2或X=-3所以(x+3)(x-2)

1+x+x^2+x^3+.+x^99+x^100

这个就是等比数列的求和,将每一项可看做一部分,如a1=1,a2=x……a101=x^100根据等比数列的求和公式,a1(首项)=1,末项a101=x^100,公比q=x,n=101则Sn=1+x+x^

3x×2x=?

是6X的平方再问:是6(x²)还是(6x)²再答:6(x²)再问:谢谢,

方程x+1x+2+x+8x+9=x+2x+3+x+7x+8

原方程变形为:x+1x+2-x+2x+3=x+7x+8-x+8x+9,去分母,得(x+2)(x+3)=(x+8)(x+9),整理,得12x+66=0,解得x=-5.5,经检验,x=-5.5是原方程的解

分式:计算1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+...+1/(x-99)(x-100)

思路:我们知道:1/3*2=(3-2)/3*2=3/3*2-2/3*2=1/2-1/3类比得:1/n*(n-1)=[n-(n-1)]/n*(n-1)=n/n*(n-1)-(n-1)/n*(n-1)=1

(3x/x-1-x/x+1)×x²-1/x 其中x=根号2-2 先化简

原式={[3x(x+1)-x(x-1)]/(x-1)(x+1)}*(x-1)(x+1)/x=[3x(x+1)-x(x-1)]/x=(3x平方+x-x平方+x)/x=2x+4当x=根号2-2时原式=2x

x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)

等于(x-1)(x-2)(x-3)(x-4)...(x-50)的导数

x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4

/>(x+2)/(x+1)-(x+3)/(x+2)-(x+4)/(x+3)+(x+5)/(x+4)=1+1/(x+1)-1-1/(x+2)-1-1/(x+3)+1+1/(x+4)=1/(x+1)-1/