若x-y=2,xy=3,则x²y-xy²=

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若x-y=2,xy=3,则x²y-xy²=
已知xy/x+y=2,则代数式3x-5y+8y/-x+3xy-y的值

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若x+y分之xy=2,则-x+3xy-y分之3x-5xy+3y=______

xy/(x+y)=2解得xy=2(x+y)所以(3x-5xy+3y)/(-x+3xy-y)=(3/2*xy-5xy)/(-1/2*xy+3xy)=-7/5

(-3x^y+2xy)-( )=4x^+xy

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

若1/x+1/y=2,则(2x-xy+2y)÷(3x+5xy+3y)

1/x+1/y=2y+x=2xy(2x-xy+2y)=2(x+y)-xy=3xy(3x+5xy+3y)=3(x+y)+5xy=11xy(2x-xy+2y)÷(3x+5xy+3y)=3xy/11xy=3

已知x+y=6,xy=-3,则x^2y+xy^2=?

“x愚人国度”您好,很高兴为您解答!x^2y+xy^2=xy(x+y)=-3*6=-18

已知x+y=6,xy=-3,则x^2y+xy^2=

x^2y+xy^2=xy(x+y)=-3*6=-18

已知x+y=5,xy=-3,则x^2y+xy^2,

x^2y+xy^2=xy(x+y)=(-3)×5=-15

若3x^2+3xy=0且xy不等于0,则x:y=

3x²+3xy=03x²=-3xy因为x不等于0所以x=-y所以x:y=1:-1

若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6xy+3*(x-y)当时,原式=-6*1+3*

若m=x^3-3x^2y+2xy^2+3y^3,n=x^3-2x^2y+xy^2-5y^3,则2x^3-7x^y+5xy

2x^3-7x^y+5xy^2+14y^3=3(x^3-3x^2y+2xy^2+3y^3)-(x^3-2x^2y+xy^2-5y^3)=3m-n

若x+y=-1,则x^4+5x^3y+x^2y+8x^2y^2+xy^2+5xy^3+y^4=( )

=(x^4+x^3y)+(y^4+xy^3)+(4x^3y+4x^2y^2)+(4xy^3+4x^2y^2)+x^2y+xy^2=x^3(x+y)+y^3(x+y)+4x^2y(y+x)+4xy^2(

若(y-x)/xy=3,求分式(2x+3xy-2y)/(x-2xy-y)的值

3/5再问:详细过程呢再答:y-x=3xyx-y=-3xy代入得:(-6xy+3xy)/(-3xy-2xy)=-3/-5=3/5

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=

因为xy/(x+y)=1/2所以x+y=2xy原式=3(x+y)-5xy/(-x-y+3xy)=3*2xy-5xy/(-2xy+3xy)=xy/xy=1

若x+y分之xy=2,则-x+3xy-y分之3x-xy+3y=多少?

xy/(x+y)=2(x+y)/xy=1/21/x+1/y=1/2(3x-xy+3y)/(-x+3xy-y)=(3/y-1+3/x)/(-1/y+3-1/x)=[3(1/x+1/y)-1]/[(3-(

若实数x,y满足1/x-1/y=5,则分式3x-2xy-3y/x+xy-y的值等于?

1/x-1/y=5即,(y-x)/xy=5即,x-y=-5xy(3x-2xy-3y)/(x+xy-y)=[3(x-y)-2xy]/[(x-y)+xy]=(-15xy-2xy)/(-5xy+xy)=(-

若x^2-3x=1,则x^2y-3xy-y

解析:若x²-3x=1,那么:x²y-3xy-y=y(x²-3x-1)=y(1-1)=0

若y-x/xy=3,求分式2x+3xy-2y/x-2xy-y

(Y-X)÷(XY)=3可变形为Y-X=3XY(2X+3XY-2Y)÷(X-2XY-Y)=(2X-2Y+3XY)÷(X-Y-2XY)={2(x-y)+3xy}÷(X-Y-2XY)={2(3xy)+3x

若x+y=5xy,则(2x+2y-3xy)/(2xy+x+y)=? 急急急 快快快!

(2x+2y-3xy)/(2xy+x+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(10xy-3xy)/(5xy+2xy)=7xy/7xy=1如果本题有什么不明白可以追问,

若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值

x+y=5xy(2x-3xy+2y)/(x+2xy+y)=[2(x+y)-3xy]/[(x+y)+2xy]=(2×5xy-3xy)/(5xy+2xy)=7xy/7xy=1再问:若x+1/x=3,求(x